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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Radioactivity

  • question_answer
    A nucleus with Z = 92 emits the following in a sequence: \[\alpha ,\,{{\beta }^{-}},\,{{\beta }^{-}},\,\alpha ,\alpha ,\alpha ,\alpha ,\alpha ,{{\beta }^{-}},\,{{\beta }^{-}},\alpha ,\,{{\beta }^{+}},\,{{\beta }^{+}},\,\alpha \]. The Z of the resulting nucleus is                                       [AIEEE 2003]

    A)            74  

    B)            76

    C)            78  

    D)            82

    Correct Answer: C

    Solution :

               \[{{Z}_{Resuting\ nucleus}}=92-8\times 2+4\times 1-2\times 1=78\]


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