JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Radioactivity

  • question_answer
    A radioactive decay chain starts from \[_{93}N{{p}^{237}}\] and produces \[_{90}T{{h}^{229}}\] by successive emissions. The emitted particles can be                                [MP PMT 2004]

    A)            Two a-particles and one b-particle

    B)            Three \[{{\beta }^{+}}\] particles

    C)            One a particle and two \[{{\beta }^{+}}\] particles

    D)            One a particle and two \[{{\beta }^{-}}\] particles

    Correct Answer: A

    Solution :

               By using \[{{n}_{\alpha }}=\frac{A-{A}'}{4}\] and \[{{n}_{\beta }}=2{{n}_{\alpha }}-Z+Z'\]


You need to login to perform this action.
You will be redirected in 3 sec spinner