A) 1.0
B) 0.5
C) 0.25
D) 0.125
Correct Answer: D
Solution :
Using conservation of momentum \[{{P}_{daughter}}={{P}_{\alpha }}\] Þ\[\frac{{{E}_{d}}}{{{E}_{\alpha }}}=\frac{{{m}_{\alpha }}}{{{m}_{d}}}\]Þ\[{{E}_{d}}=\frac{{{E}_{\alpha }}\times {{m}_{\alpha }}}{{{m}_{d}}}\] \[=\frac{6.7\times 4}{214}=0.125\,MeV\]
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