A) \[6\alpha ,\,3\beta \]
B) \[3\alpha ,\,4\beta \]
C) \[4\alpha ,\,3\beta \]
D) \[3\alpha ,\,6\beta \]
Correct Answer: B
Solution :
By using \[{{n}_{\alpha }}=\frac{A-{A}'}{4}\] and \[{{n}_{\beta }}=2{{n}_{\alpha }}-Z+Z'\]You need to login to perform this action.
You will be redirected in
3 sec