JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Radioactivity

  • question_answer
    In a radioactive substance at \[t=0\], the number of atoms is \[8\times {{10}^{4}}\]. Its half life period is 3 years. The number of atoms \[1\times {{10}^{4}}\] will remain after interval [MP PMT/PET 1988]

    A)            9 years                                    

    B)            8 years

    C)            6 years                                    

    D)            24 years

    Correct Answer: A

    Solution :

                       By formula \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{t/T}}\]or \[{{10}^{4}}=8\times {{10}^{4}}{{\left( \frac{1}{2} \right)}^{t/3}}\] or \[\left( \frac{1}{8} \right)={{\left( \frac{1}{2} \right)}^{t/3}}\]or \[{{\left( \frac{1}{2} \right)}^{3}}={{\left( \frac{1}{2} \right)}^{t/3}}\,\,\Rightarrow 3=\frac{t}{3}\] Hence t = 9 years.


You need to login to perform this action.
You will be redirected in 3 sec spinner