A) Less than 1 mg
B) \[\frac{1}{4}gm\]
C) \[\frac{1}{2}gm\]
D) 1 gm
Correct Answer: A
Solution :
Remaining amount \[=16\times {{\left( \frac{1}{2} \right)}^{32/2}}=16\times {{\left( \frac{1}{2} \right)}^{16}}={{\left( \frac{1}{2} \right)}^{12}}<1\ mg\]You need to login to perform this action.
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