A) 12.5%
B) 87.5%
C) 8.5%
D) 25.1%
Correct Answer: B
Solution :
\[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{\frac{t}{{{T}_{1/2}}}}}.\]Hence fraction of atoms decayed = \[1-\frac{N}{{{N}_{0}}}=1-{{\left( \frac{1}{2} \right)}^{\frac{t}{{{T}_{1/2}}}}}=1-{{\left( \frac{1}{2} \right)}^{\frac{3\times 60}{60}}}=\frac{7}{8}\] In percentage it is \[\frac{7}{8}\times 100=87.5%\]
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