JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Radioactivity

  • question_answer
    After two hours, one- sixteenth of the starting amount of a certain radioactive isotope remained undecayed. The half-life of the isotope is  [Bihar MEE 1995; Manipal MEE 1995; EAMCET 1994 MP PMT 1997; DPMT 2002; AFMC 2000, 05]

    A)            15 minutes                            

    B)            30 minutes

    C)            45 minutes                            

    D)            1 hour

    Correct Answer: B

    Solution :

                       \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{t/T}}\]\[\Rightarrow \left( \frac{1}{16} \right)={{\left( \frac{1}{2} \right)}^{2/T}}\Rightarrow {{\left( \frac{1}{2} \right)}^{4}}={{\left( \frac{1}{2} \right)}^{2/T}}\] \[\Rightarrow T=0.5\ hour\]= 30 minutes.


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