A) One alpha and one electron
B) Two deuterons and one positron
C) One alpha and one proton
D) One proton and four neutrons
Correct Answer: A
Solution :
\[_{92}{{X}^{235}}\xrightarrow{\alpha }{{\,}_{90}}{{X}^{231}}\xrightarrow{_{-1}{{e}^{0}}}\,{{\,}_{91}}{{Y}^{231}}\]
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