A) 400
B) 300
C) 200
D) 150
Correct Answer: C
Solution :
\[A={{A}_{0}}{{\left( \frac{1}{2} \right)}^{\frac{t}{{{T}_{1/2}}}}}\]Þ\[100=1600\,{{\left( \frac{1}{2} \right)}^{\frac{8}{{{T}_{1/2}}}}}\]Þ \[{{T}_{1/2}}=2sec\] Again at t = 6 sec, \[A=1600\,{{\left( \frac{1}{2} \right)}^{\frac{6}{2}}}=200\]counts/sec
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