A) \[\frac{1}{2}\] sec
B) 1 sec
C) \[\frac{3}{8}\] sec
D) \[\frac{3}{4}\] sec
Correct Answer: C
Solution :
\[\frac{3}{4}th\] active decay takes place in time \[t=2\,({{T}_{1/2}})\] Þ \[\frac{3}{4}=2\,({{T}_{1/2}})\] Þ \[{{T}_{1/2}}=\frac{3}{8}\sec \]You need to login to perform this action.
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