JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Radioactivity

  • question_answer
    Half lives of two radioactive substances A and B are respectively 20 minutes and 40 minutes. Initially the sample of A and B have equal number of nuclei. After 80 minutes, the ratio of remaining number of A and B nuclei is [CBSE PMT 1998; JIPMER 2000]

    A)            1 : 16                                        

    B)            4 : 1

    C)            1 : 4                                          

    D)            1 : 1

    Correct Answer: C

    Solution :

                       For 80 minutes, number of half-lives of sample \[A={{n}_{A}}=\frac{80}{20}=4\] and number of half-lives of sample \[B={{n}_{B}}=\frac{80}{40}=2.\]Also by using \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\]                    Þ \[N\propto \frac{1}{{{2}^{n}}}\]Þ \[\frac{{{N}_{A}}}{{{N}_{B}}}=\frac{{{2}^{{{n}_{B}}}}}{{{2}^{{{n}_{A}}}}}=\frac{{{2}^{2}}}{{{2}^{4}}}=\frac{1}{4}\]


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