A) 0.3%
B) 1%
C) 31%
D) 3.125%
Correct Answer: D
Solution :
Fraction of atoms remains after five half lives \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{t/T}}={{\left( \frac{1}{2} \right)}^{5T/T}}=\frac{1}{32}\] Þ Percentage atom remains \[=\frac{1}{32}\times 100=3.125%\]
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