JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Radioactivity

  • question_answer
    The nucleus \[_{48}^{115}Cd\] after two successive \[{{\beta }^{-}}\] decays will give                     [CBSE PMT 1992; JIPMER 2000]

    A)            \[_{46}^{115}Pa\]              

    B)            \[_{49}^{114}In\]

    C)            \[_{50}^{113}Sn\]              

    D)            \[_{50}^{115}Sn\]

    Correct Answer: D

    Solution :

               \[_{48}C{{d}^{115}}{{\xrightarrow{_{2(-1}{{\beta }^{o}})}}_{\,50}}S{{n}^{115}}\]


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