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JEE Main & Advanced Physics Nuclear Physics And Radioactivity Question Bank Radioactivity

  • question_answer
    An element A decays into element C by a two-step process : \[A\to B+{{\ }_{2}}H{{e}^{4}}\]\[B\to C+\ 2{{e}^{-}}\] Then  [CBSE PMT 1994; AMU 2002; KCET 2003]

    A)            A and C are isotopes         

    B)            A and C are isobars

    C)            A and B are isotopes         

    D)            A and B are isobars

    Correct Answer: A

    Solution :

               \[\alpha \]decay decreases the mass number by 4 and atomic number by 2, \[\beta \]decay increases the atomic number by 1. Here atomic number of C is same as that of A.


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