A) 0.230 per minute
B) 0.461 per minute
C) 0.691 per minute
D) 0.922 per minute
Correct Answer: B
Solution :
\[A={{A}_{0}}{{e}^{-\lambda t}}\Rightarrow 975=9750\ {{e}^{-\lambda \times 5}}\] \[\Rightarrow {{e}^{5\lambda }}=10\] \[\Rightarrow 5\lambda ={{\log }_{e}}10=2.3026{{\log }_{10}}10=2.3026\] \[\Rightarrow \lambda =0.461\]
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