A) 12 days
B) 7 days
C) 18 days
D) 21 days
Correct Answer: D
Solution :
\[A={{A}_{0}}{{\left( \frac{1}{2} \right)}^{t/{{T}_{1/2}}}}\Rightarrow 5\times {{10}^{-6}}=64\times {{10}^{-5}}{{\left( \frac{1}{2} \right)}^{t/3}}\] \[\Rightarrow \frac{1}{128}={{\left( \frac{1}{2} \right)}^{t/3}}\Rightarrow t=21\] days
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