A) 2 hours
B) 1 hour
C) 0.5 hour
D) 0.25 hour
Correct Answer: B
Solution :
\[k=\frac{2.303}{t}\log \frac{0.8}{0.6}=2.303\log \frac{4}{3}\] \[t=\frac{2.303}{k}\log \frac{0.9}{0.675}=\frac{2.303}{k}\log \frac{4}{3}\]; \[t=1\]hour.You need to login to perform this action.
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