A) 0.384 sec
B) 0.214 sec
C) 3.84 sec
D) 0.402 sec
Correct Answer: A
Solution :
For the first order reaction \[t=\frac{2.303}{K}\log \frac{a}{a-x}\] Given: \[a=0.5\ mol/litre\]; \[a-x=0.05\ ,mol/litre\] \[K=6{{\sec }^{-1}}.\] \[t=\frac{2.303}{6}\log \frac{0.5}{0.05}=\frac{2.303}{6}\log 10\]\[=\frac{2.303}{6}=0.384\sec \].You need to login to perform this action.
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