A) 8.73 min
B) 7.53 min
C) 0.383 min
D) 23.1 min
Correct Answer: D
Solution :
Rate \[\left( \frac{dx}{dt} \right)=K\ .\ c\]; \[1.5\times {{10}^{-2}}=K\times 0.5\] For first order \[K=\frac{1.5\times {{10}^{-2}}}{0.5}=3\times {{10}^{-2}}\min ut{{e}^{-1}}\] \[{{t}_{1/2}}=\frac{.693}{K}=\frac{.693}{3\times {{10}^{-2}}}=23.1\ \min ute\].You need to login to perform this action.
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