A) 0
B) 2
C) 1
D) 4
Correct Answer: B
Solution :
\[{{t}_{1/2}}\propto {{a}^{1-n}}\]Þ \[\frac{0.1}{0.4}=\frac{{{(200)}^{1-n}}}{{{(50)}^{1-n}}}\]Þ\[\frac{1}{4}={{\left[ \frac{4}{1} \right]}^{1-n}}={{\left[ \frac{1}{4} \right]}^{n-1}}\] Þ \[\frac{1}{{{4}^{1}}}=\frac{1}{{{4}^{n-1}}}\] \[\therefore \ \ n-1=1\]; \[n=2\].You need to login to perform this action.
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