A) - 1
B) - 2
C) 1
D) 2
Correct Answer: B
Solution :
\[R=k\,{{[B]}^{n}}\]; \[\frac{1}{4}R=k{{[2B]}^{n}}\];\[4={{\left( \frac{1}{2} \right)}^{n}}\]; \[4={{2}^{-n}}\]; \[n=-2\].You need to login to perform this action.
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