JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    The rate constant for the reaction,  \[2{{N}_{2}}{{O}_{5}}\to 4N{{O}_{2}}\]\[+{{O}_{2}}\] is \[3\times {{10}^{-5}}{{\sec }^{-1}}\]. If the rate is \[2.40\times {{10}^{-5}}mol\,\,litr{{e}^{\text{-1}}}{{\sec }^{-1}}\]. Then the concentration of \[{{N}_{2}}{{O}_{5}}\](in mol litre-1) is [IIT Screening 2000]

    A)                 1.4         

    B)                 1.2

    C)                 0.04       

    D)                 0.8

    Correct Answer: D

    Solution :

               Rate = \[K({{N}_{2}}{{O}_{5}})\] hence \[2.4\times {{10}^{-5}}=3.0\times {{10}^{-5}}({{N}_{2}}{{O}_{5}})\]                                 or \[({{N}_{2}}{{O}_{5}})\] \[=0.8\,\,mol\,\,{{l}^{-1}}\]


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