A) \[2.5\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]
B) \[5.0\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]
C) \[2.5\times 10-3mol\,{{l}^{-1}}{{s}^{-1}}\]
D) \[1.0\times {{10}^{-3}}mol\,{{l}^{-1}}{{s}^{-1}}\]
Correct Answer: A
Solution :
\[A+2B\to C+D\] \[\frac{-d[A]}{dt}=5\times {{10}^{-4}}\] \[-\frac{1}{2}\frac{d[B]}{dt}=\frac{5\times {{10}^{-4}}}{2}=2.5\times {{10}^{-4}}mo{{l}^{-1}}{{\sec }^{-1}}\]You need to login to perform this action.
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