A) 1.4
B) 1.2
C) 0.04
D) 0.8
Correct Answer: D
Solution :
Rate = \[K({{N}_{2}}{{O}_{5}})\] hence \[2.4\times {{10}^{-5}}=3.0\times {{10}^{-5}}({{N}_{2}}{{O}_{5}})\] or \[({{N}_{2}}{{O}_{5}})\] \[=0.8\,\,mol\,\,{{l}^{-1}}\]You need to login to perform this action.
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