A) \[60\times {{10}^{-3}}\]
B) \[20\times {{10}^{-3}}\]
C) 1.200
D) \[10.3\times {{10}^{-3}}\]
Correct Answer: A
Solution :
\[\frac{-\,d({{N}_{2}})}{dt}=-\frac{1}{3}\frac{d({{H}_{2}})}{dt}=\frac{1}{2}\frac{d(N{{H}_{3}})}{dt}\]=\[\frac{3}{2}\times 40\times {{10}^{-3}}\] \[=60\times {{10}^{-3}}.\]You need to login to perform this action.
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