• # question_answer The velocity constant of a reaction at 290 K was found to be $3.2\times {{10}^{-3}}$. At 300 K it will be  [MP PMT 2004] A)                 $1.28\times {{10}^{-2}}$             B)                 $6.4\times {{10}^{-3}}$ C)                 $9.6\times {{10}^{-3}}$               D)                 $3.2\times {{10}^{-4}}$

Solution :

As we know that the velocity constant become double by increasing the temperature by 10°C so if at 290 K, velocity constant $=3.2\times {{10}^{-3}}$ then at 300 K, velocity constant $=2({{K}_{290}})$$=2\times 3.2\times {{10}^{-3}}$$=6.4\times {{10}^{-3}}$.

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