• # question_answer The rate law for the reaction                 $RCl+NaOH(aq)\to ROH+NaCl$ is given by Rate $={{K}_{1}}[RCl]$. The rate of the reaction will be            [IIT 1988] A)                 Doubled on doubling the concentration of sodium hydroxide B)                 Halved on reducing the concentration of alkyl halide to one half C)                 Decreased on increasing the temperature of the reaction D)                 Unaffected by increasing the temperature of the reaction

$R=K[RCl]$, if [RCl] =1/2, then rate = R/2.