A) \[2\times {{10}^{2}}yrs\]
B) \[3\times {{10}^{3}}yrs\]
C) \[3.5\times {{10}^{4}}yrs\]
D) \[4\times {{10}^{3}}yrs\]
Correct Answer: B
Solution :
\[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{2.31\times {{10}^{-4}}}=0.3\times {{10}^{4}}yrs\] \[=3.0\times {{10}^{3}}yrs.\]You need to login to perform this action.
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