A) 3000 years old
B) 6000 years old
C) 9000 years old
D) 1200 years old
Correct Answer: B
Solution :
\[N={{N}_{0}}\times {{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{1}{2}=1\times {{\left( \frac{1}{2} \right)}^{n}}\]; \[n=1\] \[t=n\times {{t}_{1/2}}=1\times 6000=6000\,\text{yrs}.\]
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