A) Sr + Pb
B) Cs + Rb
C) Kr + Cd
D) Ba + Kr
Correct Answer: D
Solution :
\[_{92}{{U}^{235}}{{+}_{0}}{{n}^{1}}\to {{\,}_{56}}B{{a}^{145}}{{+}_{36}}K{{r}^{88}}+3_{0}^{1}n\]
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