A) \[4.1\times {{10}^{18}}\]
B) \[3.7\times {{10}^{17}}\]
C) \[2.05\times {{10}^{15}}\]
D) \[4.7\times {{10}^{10}}\]
Correct Answer: A
Solution :
1 milli curie = \[3.7\times {{10}^{7}}dps\] 1.5 milli curie = \[5.55\times {{10}^{7}}dps\] \[\frac{5.55\times {{10}^{7}}}{{{N}_{o}}}=\lambda =1.37\times {{10}^{-11}}\]You need to login to perform this action.
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