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JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Rate of decay and Half-life

  • question_answer
    The decay constant of \[R{{a}^{226}}\] is \[1.37\times {{10}^{-11}}{{\sec }^{-1}}\]. A sample of  \[R{{a}^{226}}\] having an activity of 1.5 millicurie will contain ...... atoms

    A)                 \[4.1\times {{10}^{18}}\]             

    B)                 \[3.7\times {{10}^{17}}\]

    C)                 \[2.05\times {{10}^{15}}\]           

    D)                 \[4.7\times {{10}^{10}}\]

    Correct Answer: A

    Solution :

           1 milli curie     = \[3.7\times {{10}^{7}}dps\]                    1.5 milli curie  = \[5.55\times {{10}^{7}}dps\]                                 \[\frac{5.55\times {{10}^{7}}}{{{N}_{o}}}=\lambda =1.37\times {{10}^{-11}}\]


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