JEE Main & Advanced Chemistry Surface & Nuclear Chemistry / भूतल और नाभिकीय रसायन Question Bank Rate of decay and Half-life

  • question_answer
    Amount of \[_{53}{{I}^{128}}({{t}_{1/2}}=25\ \min )\] left after 75 minutes is [DCE 2002]

    A)                 \[1/6\] 

    B)                 \[1/4\]

    C)                 \[1/8\] 

    D)                 \[1/9\]

    Correct Answer: C

    Solution :

                    \[\frac{N}{{{N}_{o}}}={{\left( \frac{1}{2} \right)}^{\frac{T}{{{t}_{1/2}}}}}\];\[\frac{N}{{{N}_{o}}}={{\left( \frac{1}{2} \right)}^{\frac{75}{25}}}\];  \[\frac{N}{{{N}_{o}}}={{\left( \frac{1}{2} \right)}^{3}}=\frac{1}{8}\]


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