A) 16 hr
B) 12 hr
C) 8 hr
D) 4 hr
Correct Answer: B
Solution :
\[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\Rightarrow \frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] or \[\frac{1}{64}={{\left( \frac{1}{2} \right)}^{n}}\Rightarrow {{\left( \frac{1}{2} \right)}^{6}}={{\left( \frac{1}{2} \right)}^{n}}\Rightarrow n=6\] \[T={{t}_{1/2}}\times n=2\times 6=12\] hours. After 12 hours, sample became non-hazardous.
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