A) 4
B) 6
C) 7
D) 5
Correct Answer: D
Solution :
Let\[\frac{x}{9}=\frac{y}{7}=\frac{z}{4}=k.\] Then\[x=9k,\,\,y=7k,\,\,z=4k\] \[\therefore \] \[\frac{x+y+z}{z}=\frac{9k+7k+4k}{4k}=\frac{20k}{4k}=5\]You need to login to perform this action.
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