A) \[\frac{a}{b}\]
B) \[\frac{c}{d}\]
C) \[\frac{e}{f}\]
D) All of these
Correct Answer: D
Solution :
\[\frac{a}{b}=\frac{c}{d}=\frac{e}{f}\]are in simplest form \[a=c=e\]are equals. \[b=d=f\] Then,\[\frac{6a+9c+2e}{6b+9d+2f}=\frac{12a}{12b}=\frac{a}{b}\] 1st make all in respect to\[a\] \[2nd=\frac{17c}{17d}=\frac{c}{d}\] \[3rd=\frac{17e}{17f}=\frac{e}{f}\] All of these.You need to login to perform this action.
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