A) \[xd=yc\]
B) \[2xd=yc\]
C) \[2xd-cd\]
D) \[xy-cd\]
Correct Answer: B
Solution :
\[\frac{3x+4y}{3x-4y}=\frac{3c+8d}{3c-8d}\] \[\bcancel{9xc}-24xd+12cy-\bcancel{32yd}\]\[=\bcancel{9xc}+24xd-12yc-\bcancel{32yd}\] \[-24xd-24xd=-12yc-12yc\] \[\overset{2}{\mathop{-\bcancel{48xd}}}\,=-\bcancel{24yc}\] \[2xd=yc\]You need to login to perform this action.
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