A) \[\frac{1}{n}\]
B) \[\frac{2}{n}\]
C) \[\frac{2(n-1)}{n}\]
D) \[\frac{2}{n(n+1)}\]
Correct Answer: A
Solution :
(a): \[\frac{1}{2}\times \frac{2}{3}\times \frac{3}{4}\times \frac{4}{5}\times \frac{5}{6}\times ......\times \frac{n-1}{n}=\frac{1}{n}\]You need to login to perform this action.
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