A) \[\frac{9}{119}\]
B) \[\frac{95}{119}\]
C) \[\frac{19}{119}\]
D) \[1\frac{9}{119}\]
Correct Answer: B
Solution :
\[\frac{x}{y}=\frac{9}{8}\] (Given) \[\therefore \] \[\left( \frac{6}{7}+\frac{y-x}{y+x} \right)\,\,=\,\left( \frac{6}{7}+\frac{y\left( 1-\frac{x}{y} \right)}{y\left( 1+\frac{x}{y} \right)} \right)\] \[=\frac{6}{7}+\left( \frac{1-\frac{9}{8}}{1+\frac{9}{8}} \right)=\frac{6}{7}+\left( \frac{\frac{-1}{8}}{\frac{17}{8}} \right)\] \[=\frac{6}{7}+\left( \frac{-1}{8}\times \frac{8}{17} \right)=\frac{6}{7}-\frac{1}{17}=\frac{102-7}{119}=\frac{95}{119}\]
You need to login to perform this action.
You will be redirected in
3 sec
