Answer:
According to lens maker's formula, \[\frac{1}{f}=(\mu -1)\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\] i.e., \[f\propto \frac{1}{\mu -1}\] As \[^{l}{{\mu }_{g}}{{<}^{a}}{{\mu }_{g}}\] so the focal length of the lens will increase when it is completely immersed in the liquid.
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