Answer:
\[\frac{1}{f}={{(}^{1}}{{\mu }_{2}}-1)\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\] \[\left[ {{\because }^{1}}{{\mu }_{2}}=\frac{{{\mu }_{2}}}{{{\mu }_{1}}} \right]\] If \[{{\mu }_{1}}={{\mu }_{2}},\] the refractive index of the lens and the surrounding medium is the same: \[\frac{1}{f}=0\] or \[f=\infty \] The lens in the liquid will act like a plane sheet of glass. No, the liquid is not water.
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