Answer:
Here \[{{R}_{1}}=+R,\] \[{{R}_{2}}=-R\]and \[f=R\] \[\because \] \[\frac{1}{f}=(\mu -1)\left[ \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right]\] \[\because \] \[\frac{1}{R}=(\mu -1)\left[ \frac{1}{R}+\frac{1}{R} \right]=\frac{(\mu -1)2}{R}\] or \[\mu =\mathbf{1}\mathbf{.5}\]
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