A) 8
B) 6
C) 4
D) 5
Correct Answer: A
Solution :
Let us find H.C.F. of 120 and 224. \[=\sqrt{64+36}=10\,cm\] \[\Rightarrow \] \[x=\frac{1740}{29}=60\]and\[\Rightarrow \] Thus, H.C.F. (224, 120) = 8. Now, find the H.C.F. of 8 and the third number 256. \[140\times 605=11\times L.C.M.\] i.e., H.C.F. (256, 8) = 8 Hence, the largest required number is 8.You need to login to perform this action.
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