A) \[\frac{mx}{{{(m+1)}^{2}}}\]
B) \[\frac{mx}{{{(m-1)}^{2}}}\]
C) \[\frac{{{(m+1)}^{2}}}{m}x\]
D) \[\frac{{{(m-1)}^{2}}}{m}x\]
Correct Answer: A
Solution :
\[\frac{v}{-u}=-m\,\,\text{and}\,\text{ }v+u=x\Rightarrow u=\frac{x}{1+m}\] \[\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\Rightarrow f=\frac{mx}{{{(m+1)}^{2}}}\].You need to login to perform this action.
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