JEE Main & Advanced Physics Ray Optics Question Bank Refraction at Curved Surface

  • question_answer
    A point object O is placed in front of a glass rod having spherical end of radius of curvature 30 cm.  The image would be formed at                                                                   [Orissa JEE 2002]

    A)            30 cm left

    B)            Infinity

    C)            1 cm to the right

    D)            18 cm to the left

    Correct Answer: A

    Solution :

                       By using formula \[\frac{{{\mu }_{2}}}{v}-\frac{{{\mu }_{1}}}{u}=\frac{{{\mu }_{2}}-{{\mu }_{1}}}{R}\]                    \[\Rightarrow \]\[\frac{1.5}{v}-\frac{1}{(-15)}=\frac{(1.5-1)}{+30}\Rightarrow v=-\,30\,cm\].            Negative sign shows that, image is obtained on the same side of object i.e. towards left.


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