A) Plane mirror
B) Convex mirror of focal length 2\[f\]
C) Concave mirror of focal length \[f/2\]
D) None of the above
Correct Answer: C
Solution :
Focal length of effective lens \[\frac{1}{F}=\frac{2}{{{f}_{l}}}+\frac{1}{{{f}_{m}}}=\frac{2}{{{f}_{l}}}+\frac{1}{\infty }\Rightarrow F=\frac{{{f}_{l}}}{2}\]
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