A) No image
B) A virtual enlarged image
C) A real enlarged image
D) A real smaller image
Correct Answer: C
Solution :
For lens (1) \[\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\Rightarrow \frac{1}{(+8)}=\frac{1}{v}-\frac{1}{(-12)}\] \[\Rightarrow v=24\]\[cm\] i.e. Image \[A'B'\] is obtained 6 cm before the lens 2 or at the focus of lens 2. Hence final image formed by lens 2 will be real enlarged and it is obtained at \[\infty \].You need to login to perform this action.
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