A) \[\frac{3}{2}\] m
B) \[\frac{1}{4}\]\[m\]
C) 4 m
D) \[\frac{1}{8}\]\[m\]
Correct Answer: B
Solution :
Combined power \[P={{P}_{1}}+{{P}_{2}}=6-2=4D\]. So focal length of combination \[F=\frac{1}{P}=\frac{1}{4}m\]You need to login to perform this action.
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