A) \[{{\omega }_{1}}{{f}_{1}}={{\omega }_{2}}{{f}_{2}}\]
B) \[{{\omega }_{1}}{{f}_{2}}+{{\omega }_{2}}{{f}_{1}}=0\]
C) \[{{\omega }_{1}}+{{f}_{1}}={{\omega }_{2}}+{{f}_{2}}\]
D) \[{{\omega }_{1}}-{{f}_{1}}={{\omega }_{2}}-{{f}_{2}}\]
Correct Answer: B
Solution :
For achromatic combination, \[\frac{{{w}_{1}}}{{{f}_{1}}}+\frac{{{w}_{2}}}{{{f}_{2}}}=0\] Þ \[{{w}_{1}}{{f}_{2}}+{{w}_{2}}{{f}_{1}}=0\]You need to login to perform this action.
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